Ai trả lời mình đi cho đỡ quê 😞💔

a: \(=\left(x+2-y\right)\left(x+2+y\right)\)

c: \(=\left(x-y\right)^2\)

\(a)\)\(3x^2-6xy+3y^2-12\)

\(=\)\(3\left(x^2-2xy+y^2\right)-12\)

\(=\)\(3\left(x-y\right)^2-12\)

\(=\)\(3\left[\left(x-y\right)^2-4\right]\)

\(=\)\(3\left(x-y-4\right)\left(x-y+4\right)\)

\(b)\)\(x^2+5x+6\)

\(=\)\(\left(x^2+2x\right)+\left(3x+6\right)\)

\(=\)\(x\left(x+2\right)+3\left(x+2\right)\)

\(=\)\(\left(x+2\right)\left(x+3\right)\)

Chúc bạn học tốt ~ 

a) 3x²-6xy+3y²-12=3(x²-2xy+y²)-12=3(x-y)²-12=3[(x-y)²-4]=3(x-y-2)(x-y+2)

b)x²+3x+2x+6=x(x+3)+2(x+3)=(x+3)(x+2)

aaaaaa.. nhầm đoạn cuối bn êi :v 

\(=\)\(3\left(x-y-2\right)\left(x-y+2\right)\) mới đúng nhé =.= 

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a) \(x^3y^3+125=\left(xy\right)^3+5^3=\left(xy+5\right)\left(x^2y^2-5xy+25\right)\)

b) \(8x^3+y^3-6xy\left(2x+y\right)=\left(8x^3+y^3\right)-6xy\left(2x+y\right)=[\left(2x\right)^3+y^3]-6xy\left(2x+y\right)\)

\(=\left(2x+y\right)\left(4x^2-2xy+y^2\right)-6xy\left(2x+y\right)=\left(2x+y\right)\left(4x^2-2xy+y^2-6xy\right)\)

\(=\left(2x+y\right)\left(4x^2-8xy+y^2\right)\)

c) \(\left(3x+2\right)^2-2\left(x-1\right)\left(3x+2\right)+\left(x-1\right)^2\)

\(=[\left(3x+2\right)-\left(x-1\right)]^2=\left(3x+2-x+1\right)^2=\left(2x+3\right)^2=\left(2x+3\right)\left(2x+3\right)\)

a , 3x² + 3y² - 6xy - 12

= 3 ( x² + y² - 2xy - 4 )

= 3 ( x - y )² - 2²

^{= 3 ( x - y + 2 ) ( x - y - 2 )}

`a)7x^3y^2+14x^2y^3+7xy^4`

`=7xy^2(x^2+2xy+y^2)`

`=7xy^2(x+y)^2`

______________________________________________

`b)x^2-xy+5x-5y`

`=x(x-y)+5(x-y)`

`=(x-y)(x+5)`

______________________________________________

`c)3x^2-6xy-12+3y^2`

`=3(x^2-2xy-4+y^2)`

`=3[(x-y)^2-4]`

`=3(x-y-2)(x-y+2)`

a)7x³y²+14x²y³+7xy⁴

=7xy²(x²+2xy+y²)

=7xy²(x+y)²

b)x²-xy + 5x - 5y

=x(x-y) + 5(x-y)

=(x-y) (x+5)

p

`1)`

`a)3x^2-6xy+3y^2=3(x^2-2xy+y^2)=3(x-y)^2`

`b)(x-y)^2-4x^2=(x-y-2x)(x-y+2x)=(-x-y)(3x-y)`

`2)`

`a)2x(x-3)-x+3=0`

`<=>2x(x-3)-(x-3)=0`

`<=>(x-3)(2x-1)=0`

`<=>[(x=3),(x=1/2):}`

`b)x^2+5x+6=0`

`<=>x^2+2x+3x+6=0`

`<=>(x+2)(x+3)=0`

`<=>[(x=-2),(x=-3):}`

a) Xem lại đề

b) x³ - 4x²y + 4xy² - 9x

= x(x² - 4xy + 4y² - 9)

= x[(x² - 4xy + 4y² - 3²]

= x[(x - 2y)² - 3²]

= x(x - 2y - 3)(x - 2y + 3)

c) x³ - y³ + x - y

= (x³ - y³) + (x - y)

= (x - y)(x² + xy + y²) + (x - y)

= (x - y)(x² + xy + y² + 1)

d) 4x² - 4xy + 2x - y + y²

= (4x² - 4xy + y²) + (2x - y)

= (2x - y)² + (2x - y)

= (2x - y)(2x - y + 1)

e) 9x² - 3x + 2y - 4y²

= (9x² - 4y²) - (3x - 2y)

= (3x - 2y)(3x + 2y) - (3x - 2y)

= (3x - 2y)(3x + 2y - 1)

f) 3x² - 6xy + 3y² - 5x + 5y

= (3x² - 6xy + 3y²) - (5x - 5y)

= 3(x² - 2xy + y²) - 5(x - y)

= 3(x - y)² - 5(x - y)

= (x - y)[(3(x - y) - 5]

= (x - y)(3x - 3y - 5)

a, ( x-y)²=4

3x^2 +3y^2 -6xy -12

=3(x^2 - 2xy +y^2 - 2^2  )

=3 (x-y)^2 - 2^2 

=3(x-y-2)(x-y+2)

3(x+y) -(x^2+2xy+y^2)

=3(x+y) -(x+y)^2 

(x+y)(3-x-y)